Test the claim that the proportion of men who own cats is
significantly different than the proportion of women who own cats
at the 0.01 significance level.
The null and alternative hypothesis would be:
H0:pM=pFH0:pM=pF
H1:pM<pFH1:pM<pF
H0:μM=μFH0:μM=μF
H1:μM>μFH1:μM>μF
H0:pM=pFH0:pM=pF
H1:pM>pFH1:pM>pF
H0:pM=pFH0:pM=pF
H1:pM≠pFH1:pM≠pF
H0:μM=μFH0:μM=μF
H1:μM≠μFH1:μM≠μF
H0:μM=μFH0:μM=μF
H1:μM<μFH1:μM<μF
The test is:
two-tailed
left-tailed
right-tailed
Based on a sample of 20 men, 45% owned cats
Based on a sample of 40 women, 60% owned cats
The test statistic is: (to 2 decimals)
The p-value is: (to 2 decimals)
Based on this we:
a)
H0 : pM=pF
H1 : pM≠pF
The test is two tailed
test statistics:
pcap = (p1 *n1+ p2*n2)/(n1+n2
= ( 0.45 * 20+ 0.60 * 40)/(20+40)
= 0.55
z = ( p1- p2)/sqrt(pcap *(1-pcap) *(1/n1+1/n2))
= ( 0.45 - 0.60)/sqrt(0.55*(1-0.55)/*(1/20+1/40))
= -1.10
The p value is 0.27
Based on this we:
Fail to reject the null hypothesis as p value . 0.01 significan celevel
Test the claim that the proportion of men who own cats is significantly different than the...
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