An oxygen container that one can use in the mountains has a 90-min oxygen supply at a speed of
6 L/min (with the volume measured at atmospheric pressure).
A.Determine the volume of oxygen inside the container. Assume that the pressure inside the container is 6.9 × 106 N/m2 and the temperature is 20∘C.
Express your answer to two significant figures and include the appropriate units.
B.Determine the mass of the oxygen inside the container.
Express your answer to two significant figures and include the appropriate units.
Please show steps
A)
Here ,
time for oxygen , t = 90 min
volume flow rate = 6 L/min
volume of oxygen at atmospheric pressure , V = 6 * 90
V = 540 litres
Pressure , P2 = 6.9 *10^6 N/m^2
Using charles law ,
P1 * V1 = P2 * V2
540 * 1.01 *10^5 = 6.9 *10^6 * V2
V2 = 7.90 litres
the volume of oxygen container is 7.90 litres
B)
Now , using ideal gas equation
P*V = n*R*T
540 * 1 = n * 0.0821 * (20 + 273)
solving for n
n = 22.45 moles ,
mass of oxygen = 22.45 * 0.032
mass of oxygen = 0.7184 Kg
the mass of oxygen in the tank is 0.7184 kg
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