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MH2802-LINEAR ALGEBRA FOR SCIENTISTIS Quiz: Quiz 8: Details of Perspective This Question: 1 pt 3 of 11 Let the matrix below a
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Given matrix from ce is Ail, az for finding eigendues consider TA-dIl = 0 where I is identity matrix of dimension 2x2 IA-dil== 4+ Jū i 2 = 4 + 2 i 2. d 2 Ei i _Now iwo eigenvalues are 2+142-1 eigem.vector at d=2+1, *- TAL/I )x= 0 THEN where x = TI-(2R2: R2-R, -2 Le -2(1-1) The o Lezy IXLEO -- 24-261-i) x2 zo -200 = 211-i) x2 - 24 = (iinxs 245 - (1 - i) xs is ( 1 - puy ) -

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