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You are an artillery officer attached to Gaius Julius Caesar's Xth Legion in the Gallic War...

You are an artillery officer attached to Gaius Julius Caesar's Xth Legion in the Gallic War (1rst C. BCE). You are responsible for a mangonel, a device with a long spoonlike arm used to lob stones over the walls of Gallic oppida. These fortresses are protected by high walls atop a hill rising from a deep, wide moat: you must fire your missiles from the far side of the moat. Your mangonel can fire it's projectile at speed (Vo)= 60.0 m/s, independent of the angle of elevation at which you fire. Calculate the height of the highest wall you can clear from across a moat of width x=180.m, and the angle at which you must fire to achieve this. Use g= 9.81 m/s^2 as the acceleration of gravity. Assume aerodynamic forces are negligible and disregard the height of the mangonel itself. HINT: When aimed for maximum height, the projectile will not clear the wall at the top of its trajectory. A more careful analysis is needed.

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Answer #1

The equations for the projectile are

y\left ( t \right )= y_{0}+V_{0y}t-\frac{1}{2}gt^{2}__________________(1)

x\left ( t \right )= V_{0x}t_______________________________(2)

where,

V_{0x}= V_{0}\, cos\, \theta

V_{0y}= V_{0}\, sin\, \theta

Using equations (1)-(2) we get,

y\left ( x \right )= y_{0}+tan\, \theta \, x-\frac{g}{2V_{0}^{2} cos^{2}\, \theta }x^{2}

the maximum x occur for \theta = \frac{\pi }{4} , then let us try to find out the height, for that angle,

as

y_{0}= 0

y\left ( x \right )= tan\, \theta \, x-\frac{g}{2V_{0}^{2} cos^{2}\, \theta }x^{2}

the maximum distance x can be achieve when theta=pi/4

y\left ( x= 180\, m \right )= tan\, \left ( \frac{\pi }{4} \right ) \, \times 180\, m-\frac{9.81\, \frac{m}{s^{2}}}{2\left ( 60\frac{m}{s} \right )^{2} cos^{2}\, \frac{\pi }{4} }\left ( 180\, m \right )^{2}=91.71\, m

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