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A stockroom currently has 30 components of a certain type, of which 8 were provided by supplier 1, 10 by supplier 2, and 12 by supplier 3. Six of these are to be randomly selected for a particular assembly. Let X= the number of supplier 1's components sel

A stockroom currently has 30 components of a certain type, of which 8 were provided by supplier 1, 10 by supplier 2, and 12 by supplier 3. Six of these are to be randomly selected for a particular assembly. Let X= the number of supplier 1's components selected, Y= the number of supplier 2's components selected, and p(x, y) denote the joint pmf of X and Y.

a. What is p(3, 2)? [Hint: Each sample of size 6 is equally likely to be selected. Therefore, p(3, 2) = (number of outcomes with X= 3 and Y= 2)/(total number of outcomes). Now use the product rule for counting to obtain the numerator and denominator.]

b. Using the logic of part (a), obtain p(x, y). (This can be thought of as a multivariate hypergeometric distribution-sampling without repl


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Answert * For the given Question. @) use events the formula for the probability of equally likely to find p (3,2) * Find the= N (3,2) = N /* = 3).N (Y= 2). W (2=1) * Noul use the components to count the number of ways that components selected from e*(6)¥ determine the general formula for plx,y) as part (a) * Begin by finding the Number of Components from supplies 3. * Whe

answered by: ANURANJAN SARSAM
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A stockroom currently has 30 components of a certain type, of which 8 were provided by supplier 1, 10 by supplier 2, and 12 by supplier 3. Six of these are to be randomly selected for a particular assembly. Let X= the number of supplier 1's components sel
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