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Sixty-three percent of U.S. adults oppose special taxes on junk food and soda. You randomly select...

Sixty-three percent of U.S. adults oppose special taxes on junk food and soda. You randomly select 10 U.S. adults. Find the mean, variance, and standard deviation of this binomial distribution.

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Answer #1

Let X be number of adults oppose special taxes on junk food and soda. Sample size ( n ) = 10

Here, X ~ Binomial ( n = 10, p = 0.63)

Mean = E(X) = np = 10 * 0.63 = 6.3

Varaince = Var(X) = np(1-p) = 10 * 0.63 * (1-0.63) = 2.331

standard deviation = SD(X) = V2.331 -1.5268

Hence,

Mean = 6.3

Variance = 2.331

Standard deviation = 1.5268

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