Question

Q. No 3). A reverse osmosis (RO) unit is used to treat 300 m3/day municipal water. If the mass transfer coefficient is 0.2131/day-m²-(KP), at 25 °C. The pressure difference between feed and product water is 2600 KPa. Osmotic pressure difference between feed and product water is 300 KPa. Calculate the membrane area required at 15 °C. (Given: A15/A25 = 1.49).

Answer 1

FlUa Fou solution Gicoen data mass toanser coefficiene 0.23 dagem Temperature -25% pressure difference @p) - 2600kpa os motic pressure difference 300 kpa axea the membrane Now, calculating 15°c is at xquired water Klop-OT) 0-a 13(2600 - 300) -0.213 X 2300 =489.9 day-m' at 25°c Fw ouvea 300m/day membrane is A25 A25 X1000L 489.9 L/day-m A25 = 612 369 mr. Gilgen, 1.49 A 15 Aas 1.498A25 A15

A15 = 1.49&A25 = 1.49x612.369 AIS = 912.43) m at 15°c Yeruired area Hence, The memboane is - 912.431 mr 1 A 15