Question

Write the function get_factors(n) that returns a list containing all of the divisors (without remainder) of the integer n. Use the built-in function range() to create the appropriate sequence over which to run the list comprehension.
Here are some usage examples:

>>> get_factors(10) 
[1, 2, 5, 10]
>>> get_factors(2017) # a prime number
[1, 2017]
>>> get_factors(60) # highly non-prime! why we have 60 minutes per hour
[1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]
>>> get_factors(3147) # relatively prime – few factors
[1, 3, 1049, 3147]

Hint! Use a list comprehension with an if clause: x is a factor of n if dividing n by x has no remainder.

Answer 1

In this program,

- We have defined a function get_factors(n) that returns a list containing all of the divisors (without remainder) of the integer n
- Then we are using the list comprehension with an if clause to fetch all those elements which are the divisors of n.
- Then storing it in a new list.
- After that, we are printing the new list.

Code:

#Defined a function named get_factors which accepts an integer
def get_factors(n):
  
#Using list comprehension iterating from 1 to n with an if clause, then
#checking whether n after dividing with i leaves no remainder
#All such elements are then stored in the list named newList
newList=[i for i in range(1,n+1) if n%i==0]
  
#You can even print the newList or else return the newList
print(newList)

Please check the compiled program and its output for your reference:

In [8]: Defined a function named get_factors which accepts an integer def get_factors(n): #Using list comprehension iterating from 1 to n with an if clause, then #checking whether n after dividing with i Leaves no remainder #ALL such elements are then stored in the list named newlist newList=[i for i in range(1, n+1) if n%i==0] #You can even print the newlist or else return the newlist print(newlist)

Output:

In [10]: get_factors (10) [1, 2, 5, 10] In [12]: get_factors (2017) [1, 2017] In [13]: get_factors (3147) [1, 3, 1049, 3147] In [11]: get_factors (60) [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]

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