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D Question 47 5 pts A gas sample is at 338 Kwith a pressure of 1.26 atm. The molar mass of the gas is 44.01 g/mol. What is th
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47) PV=nRT

P=Pressure=1.26 atm, T=temperature=338 K ;R=0.0821 L atm K-1 mol-1,M=Molar mass is given by 44.01 g/mol

n=no of moles=given mass/Molar mass,let given mass be m,and Molar mass be M

PV=m*R*T/M ; d=density=given mass/Volume=m/V

P=[m*R*T/][M*V]

P=d *R*T/ M    (as m/V=d)

d= [P*M]/[R*T]=    [1.26 atm *44.01 g/mol]/[0.0821 L atm K-1 mol-1*338 K]

=1.998 g/L= 2 g/L

Answer= Density is

2

48) 4 HSiCl3(l)\rightarrowSiH4(g)+3 SiCl4(l)

From the balanced equation 4 moles of HSiCl3 gives 3 moles of SiCl4

When 29 moles of HSiCl3 has been consumed   [3 moles of SiCl4][29 moles of HSiCl3]/[4 moles of HSiCl3]

=21.75 moles of SiCl4 has been produced=22 moles of SiCl4(to the nearest whole number)

Answer=

22
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