Find the particular antiderivative of the following derivative that satisfies the given condition. dy dx -3...
Find the particular antiderivative of the following derivative that satisfies the given condition . dy - 3+2x-1-1; y(1) = 4 dx ***+2 y(x) =
Find the particular antiderivative of the following derivative that satisfies the given condition. dy=5x-5+3x-1-1; dx y(1):5 Find the particular antiderivative of the following derivative that satisfies the given condition. dy=5x-5+3x-1-1; dx y(1):5
Find the particular antiderivative of the following derivative that satisfies the given condition. C'(x) = 6x2 - 2x; C(O) = 3,000 C(x)=0
Find the particular antiderivative of the following derivative that satisfies the given condition. dR/dt=111/ t4, R(1)=25
find the particular solution that satisfies the initial condition dy/dx= (2x+sec^2x)/2y , y(0)=-5
problem 57 ent. "а In Problems 55–62, find the particular antiderivative of each derivative that satisfies the given condition. 55. C'(x) = 9x? 9x² – 20x; C(10) 2,500 56. R'(x) = 500 – 0.4x; R(0) = 0 dx 10 dR 50 57. 25 58. ;R(1) = 50 dt dt we of the = vix(1) p3 ; R(1) e of the for each x. C In Problems 65-70, find each indefinite integral. 65. J. dx 2 67.
Find the particular solution to the given differential equation that satisfies the given conditions. d2y 9 dy 14y= 12 - ex; 4) dx dx2 and y - 29 when x = 0 42 dy dx 2 2x A) y B) y 7 6 7 6 사우-등나을이건을. 22x+ 27x-6_1 ex 2 2x-2,7x,6_1 5 7 6 C) y D) y 7 6 Find the particular solution to the given differential equation that satisfies the given conditions. d2y 9 dy 14y= 12 -...
4.9.74 For the following function f, find the antiderivative F that satisfies the given condition. f(u)=6e" - 7: F(0) = -1 The antiderivative that satisfies the given condition is F(u) =
hind the derivative. y = 12x dy + 5x + 8x, find dx O A. dy = -24x dx - 3 + 15x2 OB. dy =- - 24x - 1 + 15x² + 8 dx O C. dy dx - 24x - 1 + 15x2 OD. dy dx -3 - - 24x + 15x2 + 8
Find the solution of the differential equation with the given initial condition. Dy/dx = 2x + sec^2x/2y, y(0) = 5.