Ho: p1 - p2 = 0
Ha: p1 - p2 > 0
sample #1 ----->
experimental
first sample size, n1=
235
number of successes, sample 1 = x1=
24
proportion success of sample 1 , p̂1=
x1/n1= 0.1021
sample #2 -----> standard
second sample size, n2 =
190
number of successes, sample 2 = x2 =
11
proportion success of sample 1 , p̂ 2= x2/n2 =
0.058
difference in sample proportions, p̂1 - p̂2 =
0.1021 - 0.0579 =
0.0442
pooled proportion , p =
(x1+x2)/(n1+n2)= 0.082
std error ,SE = =SQRT(p*(1-p)*(1/n1+
1/n2)= 0.0268
Z-statistic = (p̂1 - p̂2)/SE = (
0.044 / 0.0268 ) =
1.65
.....................
THANKS
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