Question

a-d?

A block of mass mrests on an air table (no friction), and is pulled with a force probe, producing the Force vs. acceleration graph shown below. Investigating Forces & Acceleration (a) Determine the mass of the block. The block is now placed on a rough, horizontal board having a coefficient of static friction 16-0.50, and a coefficient of kinetic (sliding) friction 0.30. A horizontal 10.0 N force is then exerted on the block. H-0.50 ; 2-0.30 (b) What is the acceleration of the block? Justify your answer.

Answer 1

(a) we know Famã in the diagram given clearly it is an equation of the form, fear so, comparing, we will get that d = m Slope So, from the graph . og er 0-25 kg so, m = 0.25 kg | 16) els = 0.50 Mx = 0.30 ² = LON While moving coefficient of Kinetic friction will be used, so E=ma = un Normal force Namg considering golomis? => 60.76) a = (0.30)x 0,95) x 10 = a - 3m/s2 1. Amacoso una cosa Umag cosa CC) when one end of the sinar board is slowly raised masing F² syma = mg sino-Using cose The block will remain Stationary as long as, yng sino = using cose

=> 0-50) - tane ą o = tanico.50) as long as a stanic), the block will remain Stationary. Increasing the angle further will cause the blocks to start moving. Here as we see there is no 'm' dependance and they are canceling out, both the masses will slide down Simultaneously. а) - 9ѕine - Д«1ose - 10 sino - 0.30 x 10x cos la = 1o Sing - 3 cose again since there is no 'm' dependance of a we conclude that both will have same accelerat".