Question 20 It is known that the surface area of a sphere of radius a >0...
Question 3. Let Q be the solid hemisphere bounded by x + y² + 2 = 1 for 2 > 0 and by the plane z = 0, and let F = xi+yi + zk be a vector field. Verify the divergence theorem for Q and F by answering parts (a) and (b) below. Part (a) (5 points). Find the value of the triple integral of the divergence of F over the solid hemisphere Q. Part (b) (10 points). Evaluate...
Let V be the solid sphere of radius a centred at the origin. Let S be the surface of V oriented with outward unit normal. Consider the vector field F(x, y, z) (xi + yj + zk) (x2 + y2 + z2)3/2 (a) Evaluate the flux integral Sle F:ñ ds by direct calculation. (b) Evaluate SIL, VF DV by direct calculation. (c) Compare your answers to parts (a) and (b) and explain why Gauss' theorem does not apply.
please just the final answer for both
Evaluate the surface Integral || 5. ds for the given vector fleld F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = yi - xj + Szk, S is the hemisphere x2 + y2 + y2 = 4, 220, oriented downward 26.677 X Evaluate the surface integral llo F.ds for the given vector field F...
Let F(x, y, z) = xi + yj + zk and S be the surface defined by z = 9 – 22 - y2 and 2 > 0. Evaluate SsFinds, where n is the upward unit normal vector.
Evaluate the surface integral F.ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation F(x, y, 2) = -xi - 1 + zk, Sis the part of the cone 2 V x2 + y2 between the planes 2 = 1 and 2 - 6 with downward orientation
Il Evaluate the surface integral F.ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = y) - zk, S consists of the paraboloid y = x2 + 22,0 Sys1, and the disk x2 + z2 s 1, y = 1. Evaluate the surface integral F.ds for the given vector field F and the oriented surface S....
Evaluate the surface integral ∫∫sF·ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y,z) = xi - zj +yk S is the part of the sphere x2 + y2 + z2 = 16 in the first octant, with orientation toward the origin.
(1 point) Compute the flux of the vector field F 3z2y2 zk through the surface S which is the cone vz2 y2 z, with 0z R, oriented downward. (a) Parameterize the cone using cylindrical coordinates (write 0 as theta). (r,)cos(theta) (r, e)rsin(theta) witho KTR and 0 (b) With this parameterization, what is dA? dA = | <0,0,(m5/2)sin^2(theta» (c) Find the flux of F through S flux
МУ Note 6.3 points Use the flow charts for line integrals and surface integrals to help you decide the best way to find the answer to the following problem. Let S be the surface that is the boundary of the baxy2+z s 9 and let A be a twice continuously differentiable vector field. It is known that the flux of the vector field F V x A through the upper hemispherev9-x-y2 with upward orientation is equal to 3. Determine the...
7. Find the surface area of the surface r(u, u) = u ui + (u + u)j + (u-u) k, u2 +02-1 V/16-x2-y2 with upward orientation and let 8. Let S be the hemisphere 2 F(x, y,z)-yitj+3z k. Calculate JJs F dS, the flux of F across S
7. Find the surface area of the surface r(u, u) = u ui + (u + u)j + (u-u) k, u2 +02-1 V/16-x2-y2 with upward orientation and let 8. Let S be...