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in the What is the momentum, in the center of mass reference frame, of a reaction +p+Kº+A if the has an energy E= 3 GeV in th

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Answer to the and part given, E = 10 MeV, 0 = 2.7 warelength of the photon (incident) 1240 1 240 1 = 1.24 x 10-4 nm Now, * =& E= he и 1240 (hm) (eV) 1 2 4o 1.266944 x 10-4 (nm) I E = 9.79 x108 eV 3 9.79610°x1,6x16 19 p E 3x108 - 2 S. 22x10-21 kg ml

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