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A 1.55 H inductor carries a steady current of 0.480 A. When the switch in the circuit is thrown open, the current is effectiv
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Answer #1

emf induced across an inductor = Ldi/dt

where L = inductance , di/dt = rate of change of current

V = 1.55*(0.48 - 0) / 0.01

= 74.4 volts

so average emf induced is 74.4 V

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