28)\
a)
for normal distribution z score =(phat-p)/p | |
here population proportion= p= | 0.400 |
sample size =n= | 200 |
std error of proportion=p=(p*(1-p)/n)= | 0.0346 |
hence probability that sample proportion will be within -/+ 0.03 of population proportion:
probability = | P(0.37<X<0.43) | = | P(-0.87<Z<0.87)= | 0.8078-0.1922= | 0.6156 |
b)
probability that sample proportion will be within -/+ 0.05 of population proportion:
probability = | P(0.35<X<0.45) | = | P(-1.44<Z<1.44)= | 0.9251-0.0749= | 0.8502 |
28. test A population proportion is .40. A random sample of size 200 will be taken...
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