If a 5.00 L container holds 1.56 mol of Ar at a temperature of 290 K,...

Question

Question

If a 5.00 L container holds 1.56 mol of Ar at a temperature of 290 K, what pressure of Ar gas would you expect?

Answer 1

Answer #1

Given, V=5.00 L n = 1.56 mol 9=290k R = 0.0821 Laten mot ko P= ? PV = nRT P=ORI = 1.56 mot x 0.0821 x atin mal Kx 290k SK = 3

Answer 2

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