Question

D Question 19 5 pts A student earned a score of 940 on a national achievement test. The mean test score was 850 with a standard deviation of 100. What proportion of students had a lower score than the student with the score of 940? (Assuime tht tet scores are normally ditributed) 0.90 0.82 0.50 0.18 0.10

Answer 1

for normal distribution z score =(X-μ)/σ
here mean=       μ=	850
std deviation   =σ=	100.0000

probability =

P(X<940)

=

P(Z<0.9)=

0.82