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Exactly 10.0 mL of water at 26.0 °C is added to a hot iron skillet. All of the water is converted to steam at 100.0°C. The ma

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Stept Given: Volume of water = soml = 10x10m Temperature at which water added = 26°C Temperature of steam = 100°C Mars of ski

Total heat required for steaming of water, Qw = 6, +Q2 = 22 600T + 30 96. 165 Qw = 25696.165 Heat lost by Skillet - Heat gain

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