QUESTION: The mean weight of watermelons found in a garden last year was 15.4 kg. In a sample of 35 watermelons at the same time this year in the same colony, the mean watermelon weight was found to be 14.6 kg. Assume the population standard deviation is 2.5 kg.
(i) At 5% significance level, can we reject the null hypothesis that the mean watermelon weight does not differ from last year?
(ii) What is the test statistics?
(iii) What is the p-value?
(iv) Find the 95% confidence interval for the population mean
(v) Why would the result in (iv) would support the decision made in part (i)
(vi) If we take another sample of size 35, what is the probability that the upper bound of the 95% confidence interval for population mean to be greater than 16kg?
Solutions for parts (i)-(iv) are explained below:
QUESTION: The mean weight of watermelons found in a garden last year was 15.4 kg. In...
a. You measure 43 watermelons' weights, and find they have a mean weight of 48 ounces. Assume the population standard deviation is 2.2 ounces. Based on this, what is the maximal margin of error associated with a 95% confidence interval for the true population mean watermelon weight? Give your answer as a decimal, to two places ± ounces b. You measure 25 watermelons' weights and find they have a mean weight of 44 ounces. Assume the population standard deviation is...
You measure the weights of 47 watermelons and find they have a mean weight of 77 ounces. Assume the population standard deviation is 14.4 ounces Based on this , construct a 95% confidence interval for the true population mean watermelon weight. ____<μ<___ , use 3 decimal places. State in words what this means in context of the problem:
You measure 33 watermelons' weights, and find they have a mean weight of 61 ounces. Assume the population standard deviation is 14.9 ounces. Based on this, construct a 99% confidence interval for the true population mean watermelon weight.
You measure 41 watermelons' weights, and find they have a mean weight of 61 ounces. Assume the population standard deviation is 11.7 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean watermelon weight.
You measure 46 watermelons' weights, and find they have a mean weight of 78 ounces. Assume the population standard deviation is 14.1 ounces. Based on this, construct a 90% confidence interval for the true population mean watermelon weight. Give your answers as decimals, to two places ______________ ± ______________ ounces
part 1. You measure 33 watermelons' weights, and find they have a mean weight of 55 ounces. Assume the population standard deviation is 9.2 ounces. Based on this, construct a 99% confidence interval for the true population mean watermelon weight. Give your answers as decimals, to two places part 2. In a survey funded by the UW school of medicine, 750 of 1000 adult Seattle residents said they did not believe they could come down with a sexually transmitted infection...
The mean weight of all babies born at a hospital last year was 7.6 pounds. A random sample of 35 babies born at this hospital this year produced the following data: 8.2 9.1 6.9 5.8 6.4 10.3 12.1 9.1 5.9 7.3 11.2 8.3 6.5 7.1 8.0 9.2 5.7 9.5 8.3 6.3 4.9 7.6 10.1 9.2 8.4 7.5 7.2 8.3 7.2 9.7 6.0 8.1 6.1 8.3 6.7 a. What is the point estimate of the mean weight of babies born at...
A simple random sample of size n is drawn. The sample mean, , is found to be 19.2, and the sample standard deviation, s, is found to be 4.6. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 35. Lower bound: I; Upper bound: (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about u if...
A researcher caught 25 wild Rattatas on UI campus and found theiraverage weight is 7.8lbs. Find the 95% confidence interval of the population mean weight of Rattatas. The population variance is unknown and the researcher estimated the sample vairance to be =. We were unable to transcribe this image5
A simple random sample of size n is drawn. The sample mean,x overbarx, is found to be 17.8 and the sample standard deviation, s, is found to be 4.4 (a) Construct a 95% confidence interval about μ if the sample size, n, is 35 Lower bound: ____ Upper bound: ______ (Use ascending order. Round to two decimal places as needed.) (b) Construct a 95% confidence interval about μ if the sample size, n, is 51 Lower bound: ____ Upper bound:...