K = 2.303/t log[A0]/[A]
K = 6.4*10^-3 min^-1
[A0] = 0.0314M
t = 64 min
K = 2.303/t log[A0]/[A]
6.4*10^-3 = 2.303/64 log0.031/[A]
log0.031/[A] = 6.4*10^-3 *64/2.303
log0.031/[A] = 0.1778
0.031/[A] = 10^0.1778
0.031/[A] = 1.5059
[A] = 0.031/1.5059 = 0.0211M = 2.11*10^-2 M >>>>answer
at 25 degrees celsius the rate constant for the first order decomposition of a pesticide solution...
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