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2. If possible, draw a simple graph with 11 edges and all vertices are of degree...
6. (4pts) Draw a simple graph with nine edges and all vertices of degree 3. (this is possible)
1. [10 marks) Suppose a connected graph G has 10 vertices and 11 edges such that A(G) = 4 and 8(G) = 2. Let nd denote the number of vertices of degree d in G. (i) List all the possible triples (n2, N3, n4). (ii) For each triple (n2, n3, nd) in part (i), draw two non-isomorphic graphs G with n2 vertices of degree 2, në vertices of degree 3 and n4 vertices of degree 4. You need to explain...
Choose the true statement. There exists a graph with 7 vertices of degree 1, 2, 2, 3, 4, 4 and 5, respectively. the four other possible answers are false There exists a bipartite graph with 14 vertices and 13 edges. There exists a planar and connected graph with 5 vertices, 6 edges and 4 faces. There exists a graph with 5 vertices of degree 2, 3, 4, 5 and 6, respectively.
8. For each of the following, either draw a undirected graph satisfying the given criteria or explain why it cannot be done. Your graphs should be simple, i.e. not having any multiple edges (more than one edge between the same pair of vertices) or self-loops (edges with both ends at the same vertex). [10 points] a. A graph with 3 connected components, 11 vertices, and 10 edges. b. A graph with 4 connected components, 10 vertices, and 30 edges. c....
Draw a planar graph(with no loops or multiple edges) for each of the following properties, if possible. If not possible, explain briefly why not. b) 8 vertices, all of degree 3 ( how many edges and regions must there be) c) has exactly 7 vertices, has an euler cycle and 3 is minimum vertex coloring number Also please draw the graph.
Discrete Math Create a graph with 4 vertices of degrees 2, 2, 3, 3 or explain why no such graph exists. If the graph exists, draw the graph, label the vertices and edges. To answer the question in the box below, write the vertex set, the edge set, and the edge-endpoint function as shown on page 627 of the text. You can copy (Ctrl-C) and paste(Ctrl-V) the table to use in your answer if you like. Vertex set- Edge set...
Discrete Mathematics 6: A: Draw a graph with 5 vertices and the requisite number of edges to show that if four of the vertices have degree 2, it would be impossible for the 5 vertex to have degree 1. Repetition of edges is not permitted. (There may not be two different bridges connecting the same pair of vertices.) B: Draw a graph with 4 vertices and determine the largest number of edges the graph can have, assuming repetition of edges...
A graph has 21 edges, two vertices of degree 5, four vertices of degree 3, and all remaining vertices have degree 2. How many vertices does the graph have? 12 10 16 O 14
Draw a simple undirected graph G that has 12 vertices, 18 edges, and 3 connected components. Why would it be impossible to draw G with 3 connected components if G has 66 edges?
1. Draw all non-isomorphic simple graphs with 5 vertices and 0, 1, 2, or 3 edges; the graphs need not be connected. Do not label the vertices of your graphs. You should not include two graphs that are isomorphic. 2. Give the matrix representation of the graph H shown below.