Assume a 5g page is made up entirely of one polysaccaride cellulose molecule (CnH2nOn), where n can be a quite large number. the atomic weights of C, H, and O are 12, 1, and 16 respectivley. How many carbon atoms are there in this page?
emperical formula = CnH2nOn
for example if n=1;
then the formula will be CH2O
molecular weight of this formula is 12+2+16 = 30;
number of moles = weight/molecular weight
if number of moles = 1, then weight = molecular weight
that means weight of one mole of CH2O = 30 grams
what is the number of moles of 5 grams of CH2O = ?
= 5/30 = 0.16 moles
that means 0.16 moles of CH2O are present in 5g of page.
In one mole, there are 6.022 x 1023 atoms, so in 0.16 moles, there are 6.022 x 1023x 0.16
carbon atoms present.
Number of carbons in 0.16moles of CH2O = 9.635 x 1022
Assume a 5g page is made up entirely of one polysaccaride cellulose molecule (CnH2nOn), where n...
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