Lee is a cadet at the Honolulu Police Academy. He was asked to make a P-Chart for reported (minor) property crimes. Lee chose a small neighborhood with 481 families. Each family is viewed as a binomial trial. Success means that the family was the victim of at least one minor property crime in the past 3 months. Police reports gave the following data for the past 12 quarters (4 years). Assume the 481 families lived in the neighborhood all 4 years.
Quarter | 1 | 2 | 3 | 4 | 5 | 6 |
r = no. of successes | 11 | 14 | 18 | 23 | 19 | 15 |
p̂ = r / 481 | 0.02 | 0.03 | 0.04 | 0.05 | 0.04 | 0.03 |
Quarter | 7 | 8 | 9 | 10 | 11 | 12 |
r = no. of successes | 12 | 16 | 13 | 22 | 24 | 19 |
p̂ = r / 481 | 0.02 | 0.03 | 0.03 | 0.05 | 0.05 | 0.04 |
Make a P-Chart. (Use 4 decimal places.)
Center line | = ![]() |
–2.0 SL | = |
2.0 SL | = |
–3.0 SL | = |
3.0 SL | = |
List any out-of-control signals by type (I, II, or III). (Select all that apply.)
Out-of-control signal I occurs on Quarter 11.There are no out-of-control signals.Out-of-control signal III occurs on Quarter 1.Out-of-control signal III occurs on Quarter 7.
number of samples m= | 12.00 | ||||
sample size n= | 481.00 | ||||
total number of units =mn= | 5772.00 | ||||
number of defects d = | 206.00 | ||||
hence non conforming fraction p̅=d/(mn)= | 0.0357 | ||||
standard error =√(p*(1-p)/n) =0.0085
control line (CL) = p̅= | 0.0357 |
-2.0SL = 0.0357-2*0.0085 =0.0188
2SL =0.0357+2*0.0085 =0.0526
-3.0SL = 0.0357-3*0.0085 =0.0103
3.0SL =0.0357+3*0.0085 =0.0611
.There are no out-of-control signals
Lee is a cadet at the Honolulu Police Academy. He was asked to make a P-Chart...