Question

Need help with the first picture. Data provided in pictures #2 & #3

Determining the Activation Energy and Collision Frequency Factor for Reaction 1 Part 1. Transfer the reaction rate for runs 9.12 from Data Sheet 3. Then calculate the rate constant (R) at each temperature based on the reaction orders determined in parts and Record the results in Tables * = 18,0 ->15.0416"5,0216" Equation 6 ->25 10 2. Calculate the natural logarithm of the rate constant. In ) and record the results in Tables 3. Convert the reaction temperature for Runs 9-12 to Kelvin, then calculate 1/T. Table 5 Data Analysis for Arrhenius Equation lysis for Arheong Equation Run 101 Run 11 | Run 12 2. M/S 13.8x100Nys 1.3 x 10-NYS 1.7x10²nys | 2.6x10²4 nstant, k 1.5 x 103 / 5.2x10 Ys 6.8 x 10 / 1.048 10 y 1-6.502 -5.259 -4.99 1-4.565 1 Run temp, K 290.65K 296.55K 303.15 K 313.15 K 1/1,1/K 13.56x10 / 3.37x10 / 3.30x10²1/ 3.19 x 10 x Ink When the natural log of the rate constant is plotted against the inverse temperature, the slope of the line is related to the reaction's activation energy and the y-intercept is related to the collision frequency factor. Ink = - 1) + In A Equation 3 4. Using a graphing program, prepare a graph of Inkly-axis) versus 1/T (x-axis) for runs 9-12. Insert a linear regression trendline. Correlation Value: Equation of Line: 5. Use the slope of the trendline to calculate the activation energy (E.) for Reaction 1 (see page 3). 6. Use the y-intercept of the trendline to calculate the frequency factor (A) for Reaction 1 (see page 3). 7. Rewrite the Arrhenius Equation for this reaction below: Rev F2019

Answer 1

01 0.00315 0.0032 0.00325 0.0033 0.00335 0.0034 0.00345 0.0035 0.00355 0.0036 Ink y=-5298.x + 12.44 1/T

Calculation - Chart in Microsoft Office Word - Microsoft Excel Home Insert Page Layout Formulas Data Review View f AutoSum ? Logical - Define Name JMB Recently Used A Text f Use in Formula Insert Name Formula Function (sh Financial Date & Time Manager Create from Selection Auditing Function Library Defined Names B11 f =CORREL(Table1[X-Values],Table1[Y-Values]) А в C D E F G H 1 X-Values Y-Values 2 0.00356 -6.502 0.00337 -5.259 0.0033 -4.99 0.00319 -4.565 I 3 To resize chart data range, drag lower right corner of range. -0.9892911

The trendline equation is y = -5298.x + 12.44

Correlation value = -0.9892

Q.5

Comparing with Arrhenius equation :

lnK’ = lnA + (-Ea / RT)

slope =        -Ea/R = -5298 K

   this implies that Ea = 5298 x R

unit of slope is Kelvin and unit of R is JK-1

Ea = 5298 x 8.314 J = 44047.572 J = 44.0475KJ

Q.6

Comparing intercept with lnA

lnA = 12.44

A = 252710.54

Q.7

     k = A x e Ea/ RT