An inductor in the form of a solenoid contains 639turns, is 14.0cm in length, and has a cross-sectional area of 3.60cm2. What the inductance in Henry of the solenoid?
mhu = 4 pi x 10^-7
N = 639
A = 3.6 cm^2 = 3.6 x 10^-4 m^2
l = 14 cm = 0.14 m
L = mhu N^2 A / l = 4 pi x 10^-7 x 639^2 x 3.6 x 10^-4 / 0.14 = 0.001319 H
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Inductance of solenoid = 0.001319 H
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