Question

An inductor in the form of a solenoid contains 639turns, is 14.0cm in length, and has a cross-sectional area of 3.60cm². What the inductance in Henry of the solenoid?

Answer 1

2 μΝΆ l-length of solenoid A cross-sectional area

mhu = 4 pi x 10^-7

N = 639

A = 3.6 cm^2 = 3.6 x 10^-4 m^2

l = 14 cm = 0.14 m

L = mhu N^2 A / l = 4 pi x 10^-7 x 639^2 x 3.6 x 10^-4 / 0.14 = 0.001319 H

================================================================

Inductance of solenoid =  0.001319 H