Homework Answers
ANSWER
TRUE
EXPLANATION
Global variable are the variables which can be changed by any part of the program. So, it makes it very difficult to debug them.
How it is difficult?
As its value is changed by any statement. If in case you get a wrong output, you need to track down all the statements whichever tries to access it and change it, to fix the error. So, that makes the job very hectic. So, it makes program hard to debug.
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#include <sys/time.h>
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
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for(int i=0;i<100;i++) //outer loop to run 100 times
{
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task1 code：
#include <stdio.h>
#include <sys/time.h>
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
gettimeofday(&start,0);
printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
gettimeofday(&loopstart,0); //measuring time at start of
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for(int j=0;j<1000000;j++); //outer loop to run 1000000
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long ms=(loopend.tv_sec-loopstart.tv_sec)*1000000...
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#include <stdio.h>
#include <sys/time.h>
#define DEBUG 1 //Constant is defined for true
int main()
{
struct timeval start,end; //to store time of starting and ending
of program
//if statement is added
if(DEBUG){
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printf("Time in microsecond for every second: \n"); //output
for(int i=0;i<100;i++) //outer loop to run 100 times
{
struct timeval loopstart,loopend; //to store time of starting
and ending of loop
//if statement added
if(DEBUG){
gettimeofday(&loopstart,0); //measuring time at start of
loop
}
for(int j=0;j<1000000;j++); //outer loop to...
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