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4. (Lecture 25, Continuous Time Random Process, 9 pts) Suppose that the total number of requests to a web server received bet

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Answer #1

a)

rate= 10 request per minute

for 30 second

\lambda = 10/60 * 30 = 5

P(X = 8) = =poisson(8,5,0)

=0.065278

b)

first 30 second and next 30 seconds are independent

hence required probability

= 0.065278^2

= 0.004261

c)

Inter-arrival times follow exponential distribution

P(T < 3)

= 1 -e^(-\lambdat)

= 1 - e^(-10/60 * 3)

= 0.393469

d)

P( 1 < T < 3)

= e^(-10/60*1) - e^(-10/60*3)

= 0.23995

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