Given data: 85.10, 84.62, 84.65, 84.70
Let us solve it for data point 85.10 because it seems to be little bit out of range
Step 1:
Arrange the data into increasing order (smallest to largest).
84.62, 84.65, 84.70, 85.10
Step 2
: Find the Q statistic using the following formula:
Where:· x2
suspected outlier, x1 next nearest data value, and
xn is the largest value.
Inserting the values
into the formula, we get:
Qexp = (85.10 – 84.70) / 85.10 – 84.62 = 0.4/0.48 =
0.833
Step 3: Find Q critical value for n = 4 for a confidence level 95% in the Q-table = 0.829
Step4: Compare the calculated to the tabulated critical Q-value
Q exp is greater than the Q critical (0.833 > 0.829)
Since Qexp > Qcrit, the point can be rejected at confidence level 95%
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