Question

Figure P5.13a shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P5.135)

 Figure P5.13a shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P5.135) 

image.png

Use bisection to determine the point of maximum deflection (that is, the value of x where dy/dx = 0). Then substitute this value into Eq. (P5.13) to determine the value of the maximum deflection. Use the following parameter values in your com- putation: L = 600 cm, E = 50,000 kN/cm², I = 30,000 cm, and w0 = 2.5 kN/cm.  

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Answer #1


clc
clear all
close all
L=600;
E=50000;
I=30000;
w0=2.5;
g=@(x) (w0/(120*E*I*L))*(- x*L^4 + 2*L^2*x^3 - x^5);
f=@(x) (w0/(120*E*I*L))*(- L^4 + 6*L^2*x^2 - 5*x^4);
e=1e-6;
a=0;
b=500;
iter = 0;
  
if f(a)*f(b)>=0

disp('No Root')

else

prev = (a+b)/2;
p=a;
while (abs(f(p))>e)
prev=p;

iter =iter+ 1;

p = (a+b)/2;

if f(p) == 0
p
q=1
break;

end

if f(a)*f(p)<0

b = p;

else

a = p;

end
if(iter==100)
disp('the required accuracy is not reached in 50 iterations');
end
end

end
fprintf('The maximum deflection is %f which happens at x=%f\n',abs(g(p)),p);


> How can I Plot the point of maximum
deflection versus iteration number.
3) Plot the values of the relative
approximate error of the point of
maximum deflection (𝜖𝑎,𝑥) versus
iteration number.

Ahmad dogmoah Fri, Dec 17, 2021 9:52 AM

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