public main
main proc
mov ebx, 0 ; first number
mov ecx, 1 ; second number
; edx will contain the third number (ebx + ecx )
mov eax, fib-2 ; print fib numbers (not counting the first
and second because they will be printed in the begining)
mov edx, ebx
call WriteInt ; printing the first number
mov edx, ecx
call WriteInt ; printing the second number
fib:
mov edx, ebx
add edx, ecx ; edx = eax + ebx
call WriteInt
; now we have the third number in edx
; ebx = 1st, ecx = 2nd, edx = 3rd
; to prepare ebx and ecx for the next iteration, shift the values
to the right
; ebx = 2nd, ecx = 3rd, edx = ?
mov ebx, ecx
mov ecx, edx
loop fibo
ret
main endp
end main
NOTE: explain the lines in comments for better understanding Write an assembly program (for x86 processors...
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