Question

Consider the following (unbalanced) reaction:

C6H12O6(aq) → C2H6O(aq)+CO2(g)

a). How many moles of CO22 are produced when 5.418 moles of C66H1212O66 reacts?

b) How many grams of CO22 are produced when 74.589 grams of C66H1212O66 reacts?

c) How many grams of CO22 are produced when 10.797 moles of C22H66O is produced?

d) How many grams of C66H1212O66 would you need to make 3.94 kg of C22H66O?

Answer 1

Balanced equation: C6H12O6 2 C 2 H 60 + 2002 a) From reaction mole C6H12O6 produce 2 moles 002 → 5:48 moles CH1,06 pro duce 2x54,18 moles of co, : moles of co, produced = 2x5:418 10.836 moles b) moles of CoH2O = mass of CHRO Molax mass of CH,06 = 74.589 0.4141 180 Imole CH 06 produce a moles co₂ 0:414 moles Co H12O6 produce 2X0.414 mules CO2 -0.828 moles CO2 Mass of CO = moles of Co, x molar mass of con = 0.828 x 44 36:432 grams olara ollut to lig

c) From reaction, if 2 moles C Hoo is produced 2mdes (0is produced >10.797 moles 6 Hoo is produced 10797 CO2 is produced Mass of co, = moles y molas mass 9 3 = 10.797844 475.068 d) Moles of C₂ H₂O 3.94 x 10° - 85.7 moles 46 2 moles of G Hoo need imoles (H1206 → 85-7 moles GH80 need 85-7 moles CH2 06 42.85 moles C6H12O6 Mass of CGH106 = 42.85 X180 17713 9 2017