Two thin disks are attached as shown to the right. The angle ? = 39.1°, and the masses and radii of the disks are listed in the table below. What is the moment of inertia of this composite object about an axis perpendicular to the screen, through point p?
theta= 39.1 degrees
= ( 13.8 + 8.20 ) = 22 cm = 0.22 m
= d/ 0.22 = sin( 39.1)
= d = 0.22 * ( 0.952)
= d= 0.139 m
= momentof inertia = moment of inertia disk A about axis + moment of inertia of disk B
= 1/ 4 Ma* ra^2 + 1/4 Mb*rb^2 + Mb * d^2
put values....
= 0.25* 0.926 * (0.138)^2+ 0.25* 0.475 * (0.082)^3 +0.475 * (0.139)^2
=0.0136 kg.m^2
Two thin disks are attached as shown to the right. The angle ? = 39.1°, and...
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