Answer
(A) we know that
pH= -log[H3O+]
here [H3O+] = hydronium ion concentration = 4.3*10^-8 M
pH= -log[4.3*10^-8 ] = -[-7.36] = 7.36
(B)
[H3O+] = 8.4*10^-2 M
pH= -log[8.4*10^-2 ] = -[-1.08] = 1.08
(C)
pH+pOH = 14 or pH= 14-pOH
pOH= -log[OH-] = -log[1.0*10^-5]= -[-5]= 5
pH= 14-pOH= 14-5 = 9.00
(D)
pOH= -log[OH-] = -log[0.008]= -[-2.09]= 2.10
pH= 14-pOH= 14-2.10 =11.90
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