exchange rates = {'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065': 9, '-0.0080': 12, '0.0052': 1, '-0.0052': 3, '-0.0283': 1, '-0.0087': 1, '-0.0020': 9, '-0.0290': 2, '0.0180': 3, '0.0030': 15, '-0.0170': 2, '0.0000': 63, '-0.0185': 3, '-0.0055': 5, '0.0148': 1, '-0.0053': 1, '0.0265': 1, '0.0010': 22, '-0.0015': 5, '0.0137': 1, '-0.0137': 2, '-0.0023': 2, '0.0008': 10, '0.0055': 6, '-0.0025': 6, '-0.0125': 2, '0.0040': 14, '0.0260': 1, '0.0070': 8, '0.0210': 1, '-0.0070': 8, '0.0395': 1, '-0.0040': 14, '-0.0255': 2, '0.0037': 3, '0.0060': 7, '0.0025': 7, '0.0095': 2, '-0.0100': 2, '-0.0085': 6, '-0.0248': 1, '0.0028': 8, '-0.0005': 7, '-0.0113': 1, '0.0418': 1, '-0.0075': 4, '0.0130': 4, '-0.0165': 1, '0.0020': 16, '-0.0090': 7, '0.0190': 4, '-0.0245': 1, '0.0240': 2, '-0.0225': 1, '-0.0230': 1, '-0.0295': 1, '-0.0330': 1, '-0.0139': 1, '0.0104': 1, '0.0032': 7, '-0.0117': 1, '-0.0035': 8, '-0.0010': 18, '0.0285': 1, '0.0012': 7, '-0.0202': 1, '-0.0098': 1, '0.0195': 1, '0.0075': 3, '0.0015': 8, '0.0005': 5, '-0.0130': 4, '0.0115': 1, '0.0245': 2, '0.0175': 1, '0.0155': 1, '0.0120': 3, '0.0185': 1, '-0.0078': 3, '0.0023': 2, '0.0340': 1, '-0.0105': 5, '0.0140': 2, '-0.0060': 9, '0.0125': 3, '0.0262': 1, '0.0143': 1, '-0.0120': 3, '-0.0380': 1, '-0.0095': 4, '0.0135': 2, '-0.0045': 6, '0.0100': 8, '0.0145': 2, '-0.0140': 6, '-0.0200': 1, '-0.0030': 11, '0.0035': 6, '-0.0175': 1, '0.0105': 3, '0.0080': 10, '0.0165': 3, '0.0050': 16, '0.0230': 1, '-0.0050': 3, '0.0170': 2, '-0.0110': 2, '-0.0115': 3, '0.0255': 1, '0.0300': 1, '0.0110': 6, '0.0065': 3, '-0.0205': 1, '-0.0145': 2, '-0.0150': 2, '0.0085': 1, '0.0090': 3, '-0.0022': 7, '-0.0068': 5, '-0.0128': 1, '0.0073': 1, '0.0013': 3, '0.0044': 8, '0.0081': 1, '-0.0017': 1, '-0.0061': 1, '0.0088': 1, '-0.0041': 3, '-0.0044': 8, '0.0076': 4, '0.0102': 2, '0.0043': 1, '-0.0007': 2, '-0.0042': 6, '0.0011': 2, '0.0029': 1, '-0.0049': 2, '-0.0046': 9, '-0.0009': 2, '-0.0011': 1, '-0.0101': 2, '0.0022': 3, '0.0058': 2, '-0.0047': 1, '0.0067': 1, '0.0092': 4, '-0.0002': 13, '0.0041': 1, '0.0089': 1, '-0.0021': 1, '0.0006': 11, '-0.0036': 8, '0.0024': 8, '-0.0059': 1, '0.0068': 1, '-0.0260': 1, '0.0062': 3, '0.0064': 2, '0.0004': 16, '0.0048': 3, '0.0086': 1, '0.0096': 3, '-0.0074': 3, '0.0042': 8, '0.0122': 1, '0.0014': 7, '0.0072': 2, '-0.0146': 1, '-0.0048': 6, '-0.0012': 8, '0.0094': 2, '0.0009': 2, '-0.0004': 10, '-0.0038': 6, '0.0034': 6, '0.0016': 12, '-0.0016': 6, '0.0056': 5, '-0.0084': 2, '-0.0026': 6, '-0.0006': 8, '0.0066': 3, '-0.0094': 3, '-0.0014': 8, '0.0019': 1, '0.0101': 1, '0.0186': 1, '0.0084': 1, '-0.0062': 1, '-0.0086': 2, '0.0002': 8, '-0.0072': 2, '0.0057': 2, '0.0033': 1, '-0.0033': 1, '0.0017': 1, '0.0026': 9, '-0.0032': 5, '0.0018': 9, '0.0054': 4, '-0.0155': 1, '0.0074': 3, '0.0194': 1, '0.0202': 1, '-0.0172': 1, '0.0036': 7, '-0.0092': 2, '0.0071': 1, '-0.0186': 1, '0.0162': 1, '-0.0226': 1, '-0.0154': 1, '-0.0066': 3, '-0.0112': 1, '-0.0124': 2, '-0.0106': 4, '0.0027': 1, '0.0082': 2, '-0.0148': 4, '-0.0176': 1, '-0.0024': 4, '-0.0058': 1, '-0.0018': 11, '0.0284': 1, '-0.0195': 1, '-0.0316': 1, '0.0134': 2, '-0.0108': 1, '-0.0136': 1, '-0.0034': 3, '0.0038': 6, '-0.0003': 2, '0.0256': 1, '-0.0073': 1, '-0.0054': 6, '0.0007': 1, '-0.0187': 1, '-0.0118': 1, '-0.0280': 1, '0.0174': 1, '-0.0008': 4, '0.0078': 3, '0.0278': 1, '0.0141': 1, '-0.0138': 2, '0.0091': 1, '0.0136': 1, '-0.0126': 1, '-0.0082': 1, '0.0046': 3, '-0.0203': 1, '-0.0116': 1, '-0.0179': 1, '0.0192': 2, '-0.0064': 2, '-0.0056': 1, '-0.0220': 1, '-0.0134': 1, '0.0114': 1, '-0.0152': 1, '-0.0076': 1, '0.0172': 1, '-0.0001': 1, '-0.0029': 1, '-0.0158': 1}
def count_data(d):
'''
(dict of {float:int}) -> int
Given d where the keys are exchange rate changes and values are the number of occurrences of each exchange rate change, return the total number of exchange rate changes (including duplicates).
'''
Solution:
Please find below the following method implemented.
Please note the method will count each of the values in the dictionary one by one corresponding to each key.Even if the dictionary has duplicate keys with values, python wilk replace the old value for the same key.
def count_data(d) :
count = 0
for number_of_occurances in d.values() :
count += number_of_occurances
return count
exchange rates = {'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065':...
Iy uaIdii u CIOW iiIA CADIessions. (1) 1+2*3+ (4*5+6) 7 (2) 1+2*3+ ((4*5+6) 7) (1+2 3)+(4*5+6) 7 ((1)+(2+3)) + ( (4*5+6) *7)) (5) 1+2 3+ ((4*5+6) 7 (6) 1+2 3+ (4*5+6) *7) (7) 1++2 3+ ( (4*5+6) 7) (8) 1+2*3+ ((4*5+6) 7+) (9) 1+2*3+ ( (4 5+6) *7)+ (10) 1+2 3+(9 (4*5+6) 7) (11) 1+2*3+ ( (4*5+6) 7)9 (3) 5. What are the postfix expressions of (1) (4)? Do they have the same expression? If they do not, please explain...
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please show all work
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(1 point) Let f be a permutation on the set {1, 2, 3, 4, 5, 6, 7, 8, 9), defined as follows f= 1 2 3 4 5 6 7 8 9 1 2 5 8 3 9 4 6 7 (a) Write the permutation f7 as a product of disjoint cycles, separated by commas (e.g. (1, 2), (3,4,5),...). Do not include 1-cycles (e.g. (2) ) in your answer. (b) Determine the smallest value of k > O such that...
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1. Find the Jordan canonical forms of the following matrices 0 0 -1 (c) 7 6-3 (b) 2 3 2 1 0 4 0 1 -3 -10-8-6-4 0...
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