Question

A small circular washer of radius.43 cm is held directly below a long, straight wire carrying a current of 4.2 amps to the le
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Answer #1

The magnetic field at a height h from the table

B1 = uo I /2pi*(h + a)

where uo is the constant of permeability

I = Current , a = radius of the washer

h = height of the washer from the table

B1 = 4pi*10^-7*4.2 / 2pi*(1.2 + 0.0043)

= 6.975*10^-7 T

Magnetic field in the washer when it reaches the table  

B2 = uo I /2pi*a = 4pi*10^-7*4.2 / 2pi*(0.0043) = 1.95*10^-4 T

Change in flux \Delta \Phi = A(B2 - B1)

= pi*(0.0043)^2 * ( 1.95*10^-4 - 6.975*10^-7)

= 1.13*10^-8 Wb

h = 0.5gt^2

t = sqrt(2h/g) = sqrt(2*1.2 / 9.8) = 0.494 s

emf induced = \Delta \Phi / t

= 1.13*10^-8 / 0.494 = 2.28*106-8 V

direction of induced current will be determined by lenz law which states that the current induced in a circuit due to a change in a magnetic field is directed to oppose the change in flux

so the direction of current will be in clockwise direction

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