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Hydrofluoric Acid has a dissociation constant at 25°C of 6.7 x10-4. If 1.0 mol of HF is dissolved in enough water to give 1.0
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Answer #1

. HA + H₂O - H₂ot (aq) + Frans ᎾᏭ Ꮽ = IM O 0 AA I= Teq (1-x) 2 ka CH3O+] [F] [HE] 2 = 6.9x104 1-X =) x2 - 6.7 X10-4 NeglectinI have neglected the x from the denominator because acid dissociation constant is very low .

The correct option will be b which is given at third position where answer is to be marked.

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