physics help, please show all work
Q14.
let initial speed of the bullet is v m/s.
let speed of the pendulum and bullet system after bullet gets lodged in the pendulum is v1 m/s.
as maximum height risen is 12 cm,
using conservation of energy principle:
0.5*(mass of bullet+mass of pendulum)*v1^2=(mass of bullet+mass of pendulum)*g*0.12
==>v1=sqrt(9.8*0.12/0.5)=1.533623 m/s
using conservation of linear momenutm principle between before the bullet hits the pendulum and after the bullet gets lodged in the pendulum:
mass of the bulelt*initial speed of the bullet=(mass of the bullet+mass of the pendulum)*v1
==>0.012*v=(0.012+3)*1.533623
==>v=3.012*1.533623/0.012=384.94 m/s
hence option a is correct.
Q15. let speed of the block after the bullet has emerged out of it is v m/s.
using conservation of linear momentum principle:
mass of bullet*speed of bullet before collision=mass of bullet*speed of bullet after collision+mass of the block*speed of the block after collision
==>0.01*1000=0.01*400+2*v
==>v=(0.01*1000-0.01*400)/2=3 m/s
then maximum height risen by the block=v^2/(2*g)
=3^2/(2*9.8)=0.4591 m
=45.91 cm
=46 cm (approx)
hence option d is correct.
physics help, please show all work A 12-g bullet is fired into a 3.0-kg ballistic pendulum...
A bullet of mass 8 g is fired into a 1.2 kg ballistic pendulum (a block of wood acting as the pendulum bob of a thin metal arm attached to a low friction pivot point) that is initially at rest. The bullet exits the block of wood with a speed of 180 m/s and the wooden block swings from its lowest point to a maximum height of 9.2 cm above that location. Determine the velocity of the bullet before it...
A bullet of mass 4.5 g strikes a ballistic pendulum of mass 1.7 kg. The center of mass of the pendulum rises a vertical distance of 6.3 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.
A bullet of mass 3.1 g strikes a ballistic pendulum of mass 2.7 kg. The center of mass of the pendulum rises a vertical distance of 6.1 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.
A bullet of mass 2.9 g strikes a ballistic pendulum of mass 4.7 kg. The center of mass of the pendulum rises a vertical distance of 15 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.
A 10.0 g rifle bullet is fired with a speed of 370 m/s into a ballistic pendulum with mass 7.00 kg , suspended from a cord 70.0 cm long. A) Compute the initial kinetic energy of the bullet; B) Compute the kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum. C) Compute the vertical height through which the pendulum rises.
A bullet of mass 3.3 g strikes a ballistic pendulum of mass 1.3kg. The center of mass of the pendulum rises a vertical distance of6.6 cm. Assuming that the bullet remains embedded in the pendulum,calculate the bullet's initial speed.
A9-g bullet is embedded into a 2.0 kg ballistic pendulum. What was the initial velocity of the bullet if the combined masses rise to a height of 9 cm? plz draw diagram
Find the initial sped of the bullet, v1i The ballistic pendulum is a device used to measure the speed of a fast-moving projectile such a bullet. The bullet is fired into a large block of wood suspended from some light wires. The bullet is stopped by the block, and the entire system swings up to a height h. it possible to obtain the initial speed of the bullet by measuring h and the two masses. As an example of the...
1. A 35 g bullet is fired into the bob of a ballistic pendulum of mass 4.75 kg. When the bob is at its maximum height, the string makes an angle of 55 with the vertical. The length of the pendulum is 4.0 m. Find the speed of the bullet before impact. (Hint: Consider Momentum and Energy Conservation)
In a ballistic pendulum, a bullet of mass m is fired into a stationary hanging block of mass M. On impact, the bullet is trapped inside the block, which then slides up to a maximum height of h = 4.06 cm. If the mass of the block (M) is 4.7 times larger than the mass of the bullet (m), determine the speed v which the bullet must have had prior to impact.