Question

HOME LTE 10:25 PM * 51%. newton.science.sfu.ca How many moles of C23H2708 molecules are in 199 mg of this compound? 4.61x10-4 1pts You are correct. Your receipt no. is 159-31036) PreviousTries What is the mass of 0.180 mol of this compound? 77.7 g 1pts You are correct. Your receipt no. is 159-5847 How many hydrogen atoms are in 3.65 pg of this compound? 1.38x104-35 1pts Submit Answer Incorrect. Tries 1/5 Previous Tries What is the mass of 3.42x1o8 molecules of this compound? 1.48x10 11 g 1pts Submit Answer Incorrect. Tries 1/5 Previous Tries Send Feedback

Answer 1

C we have given 3.65 p g = 3.65 times 10^-12 gram Molar mass of Hydrogen atom = 1 g/mol Mole of Hydrogen atom = Mass of Hydrogen atom/Molar Mass = 3.65 times 10^12/1 Mole = 3.65 times 10^12 Now, Number of atom of Hydrogen = Mole times N_A = Mole times 6.022 times 10^23 = 3.65 times 10^12 times 6.022 times 10^23 = 2.198 times 10^12 atoms Ans d As we have 3.42 times 10^8 molecule Molar mass of hydrogen atom = Number of Molecules/N_A = 3.42 times 10^8/6.022 times 10^23 Mole = 5.679 times 10^-16 mole Mass = Mole times Molar mass = 5.679 times 10^-16 times 1 = 5.679 times 10^-16 gram