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A rotating disk of Radius b has a small central hole of Radius a(< < b)

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10.1. A rotating disk of radius \(b\) has a small central hole of radius \(a(\ll b)\). If all the surfaces of the disk are traction-free, show that the hole causes a stress concentration of 2 - i.e. that the maximum tensile stress is twice large as that in a similar disk without a hole, rotating at the same speed.

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> **is twice as large as...

Harry Smi Wed, Jun 9, 2021 6:38 PM

> Please help

Harry Smi Wed, Jun 9, 2021 6:38 PM

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Solution: a) state of stress at the inner surface at a rotating shaft: a= loomm, b=20omm N=2500rpm, 5=2700 kg/m3 0=0.3, Ty= 208 orzo forzo T2= 25.72 X106 pa 97=25.72 MP lot = 25.72 mpa] state of stress:- Ton=oy=0 [y=%7= 25.72 MPa (at x=b) Tay=0 g) Ac125X106 = 375.36.2 Zan > WE 577.12 rad/s or 2TINI 60 577.12 s =m Maximum speed. N = 5511.08 RPM Any (part b)Thanks

answered by: ANURANJAN SARSAM

> Thanks so much!!!

Harry Smi Thu, Jun 10, 2021 6:49 PM

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