Question

Draw the arrow on the conductor to show which way it will move when the current flows as indicated

Answer 1

when current flows, force is given by

F=I*cross product of L and B

where I=current

L=length of the wire and direction given by the direction of the current

B=magnetic field

case a:

magnetic field is from N to S , hence along +ve x axis.

current will be from +ve to -ve terminal. hence along -ve y axis

then magnetic force will be along cross product of -ve y and +ve x=+ve z axis

so the wire will move vertically upward.

case b:

current is along +ve y axis.

field is along -ve x axis.

cross product is along +ve z axis.

so the wire will move vertically upward.

case c:

current is along +ve y axis.

field is along +ve x axis.

cross product is along -ve z axis.

so the wire will move vertically downward.

case d:

current is along -ve z axis.

field is along +ve x axis.

cross product is along -ve y axis.

so the wire will move sideways , out of the magnet.

case e:

current is along +ve z axis.

field is along -ve x axis.

cross product is along -ve y axis.

so the wire will move sideways , out of the magnet.

case f:

current is along +ve z axis.

field is along +ve x axis.

cross product is along +ve y axis.

so the wire will move sideways ,into of the magnet.