Question

PROBLEM 5 (10 points) Consider the following code in syntax and assume stack memory allocation for nested scope is used. In the following questions, write None if none apply #include <stdlib.h> intess a; // memory a int main 0 { intes b; // memory B + inte c; // memory s c - (int) malloc(sizeof (int)); // memory 1 (int**) malloc(sizeof(int:)); // memory 2 b b - &c; a - (int***) malloc(sizeof (int**)); // memory 3 // Location 1 نها { int: x; // memory k *a - (int**) malloc(sizeof (int:)); // memory 4 * - *a; **a - (int)&a; ] // Location 2 return 0; } 1. Draw the box and circle diagram at Location 1 2. The sets of aliases at Location 1 are 3. Draw the box and circle diagram at Location 2 4. The sets of aliases at Location 2 are

Please show all your work

Answer 1

ANSWER

1.

At location 1, memory has been allocated to a, b, and c

b has been made to point to &c, a is not pointing to anyone

Hence the box-and-circle diagram is:

Garbage O value

2.

Since b is made to point to &c, (b, &c) are aliases.

Since no other pointer points anywhere, these are the only aliases at Location 1

3.

At location 2, memory has been allocated to *a

x has been made to point to *a, **a is pointing to &a

Hence the box-and-circle diagram at this point:

1) a o Mone

4.

The aliases are as follows:

• x, *a
• **a, &a