Question

Determine the following properties of superheated steam at 400 psia and 7950F. (a) Specific volume (b) Enthalpy (10)

Answer 1

a]

P = 400 psia = 2.758 x 10⁶ N/m²

T = 795 F = 697.0388 K

Assuming Steam to be an Ideal gas, the specific volume will be:

P = 400 psia = 2.758 times 106 N/m2 T = 795 F = 697.0388 K Assuming Steam to be an Ideal gas, the specific volume will be: v = RT/ PM where M = molar mass of steam = 18.02 g/mol = 0.01802 kg/mol R = 8.314 J/mol/K substitute these values to get specific volume v b] Enthalpy is given by: Delta H = c_p T Use the value of specific heat of steam at constant pressure c_p of 2.758 MPa and T = 697.0388 K and find the Enthalpy.

where M = molar mass of steam = 18.02 g/mol = 0.01802 kg/mol

R = 8.314 J/mol/K

substitute these values to get specific volume v

b]

Enthalpy is given by:

$\Delta H = c_pT$

Use the value of specific heat of steam at constant pressure c_p of 2.758 MPa and T = 697.0388 K and find the Enthalpy.