Question

Let f (x) be a periodic function on R with period 21. On the interval (-11,), f(x) is given by f(x)=sin(x) 0<x51, = Let F(x)

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Answer #1

F(x)=\left\{\begin{matrix} f(x) & if~ ~f~ ~is ~~continuous~ ~at~ ~x\\ \frac{f(x^-)+f(x^+)}{2} & if~ ~f~ ~is ~~discontinuous~ ~at~ ~x \end{matrix}\right.

The following are TRUE

\hspace{-0.6cm}F(4\pi)=\frac{f(4\pi^-)+f(4\pi^+)}{2}=\frac{f(0^-)+f(0^+)}{2}~;~~because~f~is~2\pi~periodic.\\ =\frac{1+0}{2}=\frac{1}{2}

F\left(\frac{\pi}{2} \right )=f\left(\frac{\pi}{2} \right )

The fourier series of -f(x) is -F(x)

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Note that remaining options are false. Reasons are given below

f(3\pi)=f(\pi)=0 ~;~~f~is ~2\pi ~periodic.

F(-\pi)=\frac{f(-\pi^-)+f(-\pi^+)}{2}=\frac{0+(-1)}{2}=\frac{-1}{2}

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