With what minimum speed must you toss a 160g ball straight up to hit the 13m -high roof of the gymnasium if you release the ball 1.4m above the ground? Solve this problem using energy. With what speed does the ball hit the ground?
apply KE = chnage of PE
0.5 m V^2 = mg (h2-h1)
V^2 = 2* 9.81*(13-1.4)
V = 15.08 m/s
1. energy conservation
1/2*m*v^2 + mgh1 = mgh2
v = sqrt(2*g*(h2-h1)) = 15.08m/s
when it hits ground
1/2*m*15.06^2 + m*9.8*1.4 = 1/2*m*v^2
v = 15.94m/s
With what minimum speed must you toss a 160g ball straight up to hit the 13m...
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