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Problem 5: The truss below is a bridge that supports traffic loading along its top chord. Given the traffic loading below (re

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FDJ a to 0.8 u 0.64 0.4 0.64 / I 1.16 I 3K, 4K 2K1 T 24 -0.4 0.4 IS! 3* SK 12K b). max. Tensile force. FDJ = 460.8) + 64 (3)

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