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When you look closely at the Insertion Sort you will notice that the insertion of the...

When you look closely at the Insertion Sort you will notice that the insertion of the next element into the already sorted list basically does a sequential search to determine where the element should be inserted. Consider a variation of the standard Insertion Sort algorithm that does a binary search on the already sorted part of the list to determine the location where the element should be inserted. Assuming that the keys are unique, note that a standard binary search would always return a failure. Therefore assume that you are using a slightly modified version of binary search that returns the location where the key to be inserted belongs. What is the average case cost for the number of comparisons for this new version of Insertion Sort?

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