Question

please help me with what you can, my teacher didn’t explain this well enough and i don’t ynderstand it.

Tell whether the statement is true or false 1) 8 e(16, 24, 32,40,48) True B) False 2) (4, 10, 14) -(0,4,10,14) A) True B) False Insert"" or "d" in the blank to make the statement true. 3) 14, 6, 8) (3,4,5,6, 8) B) g 4) (0, 6) (4,6) A)s B) c A) c B) g Let A- (1, 3,5, Th: B-(5, 6,7,8); C statement is true or false. (5, 8): D (1,2,3,4,5,6,7, 8). Determine whether the given (2, 5, 8); and U A) True B) False 7) BcB B) False A) True B) False A) True Find the number of subsets of the set. 9) (8, 9, 10) c) 3 D) 6 B) 7 A) 8 Decide whether the statement is true or false. 10) (9, 18, 27, 36) n(9,27) (9, 18, 27, 36) B) False A) True 11) (3, 6, 9, 12) (3, 9)-(3,6,9, 12) B) False A) True 12) (4,6, 8) n (5,7,9)-(4,6, 8, 5,7,9) B) False A) True

Answer 1

R

a elementof A means a elementof A, where A is an set. (*) And set A = B Every element of A belongs to B and every element of B belongs to A. (**) 8 phi {16, 24, 32, 40, 48} So given statement that 8 elementof {16, 24, 32, 45, 48 is False {4, 10, 14} notequalto {0, 4, 10, 14} (Because 0 NotElement {4, 10, 14}.) So given statement is False {4, 6, 8} Subsetequalto {3, 5, 4, 6, 8} (Because Every element of L.H.S set is in R.H.S set) \r\n {0, 6} is not contained in {4, 6} Because 0 NotElement {4, 6} So {0, 6} Subsetequalto {4, 6} Every set contains So. phi Subsetequalto phi. C Subsetequalto D is an true statement Because C = {5, 8} and its every element is contained in D = {2, 5, 8} B Subsetequalto B. is true since every set contains itself. U Subsetequalto A