Homework Answers
A.B = mod(A)*mod(B)*cos(thetha)
a) 6*8+7*5 = sqrt(6^2+7^2)*sqrt(8^2+5^2)*cos(theta)
=> cos(theha) = 0.954
thetha= 17.44 degree
b)
-3*3-3*4 = sqrt(3^2+3^2)*sqrt(3^2+4^2+2^2)*cos(theta)
=> cos(theha) = -0.9191
thetha = 156.79 degree
c)
-2*3+2*4 = sqrt(1^2+2^2+2^2)*sqrt(3^2+4^2)*cos(theta)
=> cos(theha) = 0.1333
thetha = 82.33 degree
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