Question

Write a C program which calculates how many digits a number has and prints each digit in reserve order with space in between(no space after the last digit). The number > 0 and has no more than 5 digits. (optional] It is better to write two functions. One is designed for printing number in reverse order and the other is for counting the number of digits. Given that the value of number (which is an int variable) is 12345, the output of your program should have the following format. 5 4 3 2 1 5 For example: Test Input Result number = 14326 14326 6 2 3 4 1 5 Answer: (penalty regime: 0 %) Reset answer 1 #include <stdio.h> 2 3v int main() { int number; scanf("%d", &number); 10 11 12 return; Check

Answer 1

Basic:-

We know that any number%10 gives the last digit of that number. eg 467%10 will give 7, 4532%10= 2 etc.

Also, any number/10 removes the last digit feom the number, eg. 467/10 will give 46, 4532/10= 453 etc.

Algorithm for reversing the number:-

1. Loop while number > 0 and perform steps 2 and 3
2. Print the number%10, this gives the last digit of number
3. Do number = number/10. This reduce the number by removing last digit.

Algorithm for finding number of digits in number:-

1. Initialize variable count = 0 . This will store number of digits.
2. Loop while number > 0 and perform steps 3 and 4
3. Do number = number/10. This reduce the number by removing last digit.
4. Increment count. (as we have seen one digit and removed it).

Input format:-

• Enter the number

Code:-

#include<stdio.h>

//function to reverse the digits of a number
void reverseNumber(int num)
{
while(num > 0) //we will perform the loop while the number > 0
{
printf("%d ", num%10); //doing %10 gives the last digit of the number
num = num/10; //doing num/10 removes the last digit from the number
}
}

//function for counting digits of number
void CountDigits(int num)
{
int count=0; //for storing count of digits
while(num > 0) //we will perform the loop while the number > 0
{
num = num/10; //doing num/10 removes the last digit from the number
count++; //we will increse the count variable as we have seen one digit
}
printf("%d", count); //print the count variable
}
  
/*Driver program to test reversDigits*/
int main()
{
int num; //for storing the number entered by user
scanf("%d", &num); //taking input from user
reverseNumber(num); //calling function to reverse digits
printf("\n"); //for line break
CountDigits(num); //calling function to count digits in number
getchar();
return 0;
}

Output:-

754834 Copy > Run Time(sec): 0 Memory(MB): 1.56€ Output: 4 3 8 4 5 7 6

Code snippet:-

4 6 9 10 1 #include<stdio.h> 2 3 //function to reverse the digits of a number void reverseNumber(int num) 5-{ while(num > 0) //we will perform the loop while the number > 7 { 8 printf("%d ", num%10); //doing %10 gives the last digit of the number num = num/10; //doing num/10 removes the last digit from the number } 11 ) 13 //function for counting digits of number void CountDigits(int num) 15 - { int count=0; //for storing count of digits while(num > 0) //we will perform the loop while the number > 0 { num = num/10; //doing num/10 removes the last digit from the number count++; //we will increse the count variable as we have seen one digit } printf("%d", count); //print the count variable 23 ) 12 14 SNNNNNドド 16 17 18 - 19 20 21 22 28 25 /*Driver program to test reversDigits*/ 26 int main() 27 - { int num; //for storing the number entered by user 29 scanf("%d", &num); //taking input from user 30 reverseNumber(num); // calling function to reverse digits 31 printf("\n"); //for line break CountDigits(num); // calling function to count digits in number 33 getchar(); 34 return; 35 ) 32